((3x^2-12)/(x^2+4x+4))/((x-2)/(x+2))

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Solution for ((3x^2-12)/(x^2+4x+4))/((x-2)/(x+2)) equation: 


D( x )

x^2+4*x+4 = 0

(x-2)/(x+2) = 0

x+2 = 0

x^2+4*x+4 = 0

x^2+4*x+4 = 0

x^2+4*x+4 = 0

DELTA = 4^2-(1*4*4)

DELTA = 0

x = -4/(1*2)

x = -2 or x = -2

(x-2)/(x+2) = 0

(x-2)/(x+2) = 0

x-2 = 0 // + 2

x = 2

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

((3*x^2-12)/(x^2+4*x+4))/((x-2)/(x+2)) = 0

((3*x^2-12)*(x+2))/((x^2+4*x+4)*(x-2)) = 0

x^2+4*x+4 = 0

x^2+4*x+4 = 0

DELTA = 4^2-(1*4*4)

DELTA = 0

x = -4/(1*2)

x = -2 or x = -2

(x+2)^2 = 0

(3*x^2-12)/((x+2)*(x-2)) = 0

3*x^2 = 12 // : 3

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { 2} 

x in { -2} 

x belongs to the empty set

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